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The value of \(\oint_C \left[ (2xy - x^2)dx + (x^2 + y^2)dy \right]\), where \(C\) is the closed region bounded by \(y = x^2\) and \(y^2 = x\)
- \(4\pi\)
- \(2\pi\)
- 0
- \(\pi\)
Answer: C
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\( S \) is any closed surface enclosing a volume \( V \) and \(\overrightarrow{F} = x \overrightarrow{i} + 2y \overrightarrow{j} + 3z \overrightarrow{k}\), if \(\iint_S \vec{F} \cdot \vec{n} \, dS = kV\), then \( k = \)
- 3
- 4
- 5
- 6
Answer: D
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If \( S \) is the surface of unit sphere \( x^2 + y^2 + z^2 = 1 \), then \(\iint_S (yz \, dy dz + xz \, dz dx + xy \, dx dy) =\)
- 0
- \(\frac{4\pi}{3}\)
- \(4\pi\)
- \(\pi\)
Answer: A
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The area of a plane region bounded by a simple closed curve \( C : x = \phi(t), y = \psi(t) \) in the \( xy \)-plane is
- \(\oint_C (x \, dy - y \, dx)\)
- \(\frac{1}{2} \oint_C (x \, dy - y \, dx)\)
- \(\frac{1}{2} \oint_C (y \, dx - x \, dy)\)
- \(\oint_C (y \, dx - x \, dy)\)
Answer: B
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The vector integral theorem which transforms surface integral into volume integral is
- Green’s Theorem
- Stokes’ Theorem
- Gauss’s Divergence Theorem
- Line Integral Theorem
Answer: C (Gauss’s Divergence Theorem)
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If \( S : x^2 + y^2 + z^2 = 1 \) then \(\iint_S x\,dy\,dz + y\,dz\,dx + z\,dx\,dy =\)
- \(\pi\)
- \(2\pi\)
- \(4\pi\)
- \(\frac{4\pi}{3}\)
Answer: C
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If \( F = xy\,i - zy\,j + x^2\,k \) and \( C : x = t^2, y = 2t, z = t^3 \) from \( t = 0 \) to \( t = 1 \) then \(\int_C F \cdot d\tau =\)
- \(\frac{51}{70}\)
- \(\frac{50}{70}\)
- \(\frac{30}{70}\)
- \(\frac{60}{70}\)
Answer: A
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If \( F = 3xy\,i - y^2\,j \) and \( C \) is the curve \( y = 2x^2 \) in the \( xy \)-plane from (0,0) to (1,2) then \(\int_C F \cdot d\tau =\)
- \(\frac{1}{6}\)
- \(-\frac{1}{6}\)
- \(\frac{7}{6}\)
- \(-\frac{7}{6}\)
Answer: D
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The value of \(\int_C \frac{dx}{x + y}\) where \( C \) is the curve \( x = at^2, y = 2at, 0 \leq t \leq 2 \)
- \(2 \log 2\)
- \(3 \log 2\)
- \(4 \log 2\)
- \(\log 2\)
Answer: A
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If \( F = (4xy - 3x^2 z^2)\,i + 2x^2\,j - 2x^3 z\,k \) and \( C : x^2 + y^2 = 1, z = 0 \) then \(\int_C F \cdot d\tau =\)
- 0
- 1
- 2
- 3
Answer: A
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If \( \vec{r} = x\vec{i} + y\vec{j} + z\vec{k} \) and \( V \) is the volume bounded by the closed surface \( S \) then \(\iint_S \vec{r} \cdot d\vec{S} =\)
- \( V \)
- \( 2V \)
- \( 3V \)
- 0
Answer: D
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If \( \vec{A} = 2x\vec{i} + 3y\vec{j} + 4z\vec{k} \) and \(\oint_C \vec{A} \cdot d\vec{r} = K\) then \( K =\)
- 9
- 2
- 0
- 4
Answer: C
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If \(\iint_S (x+z)dy\,dz + (y+z)dz\,dx + (x+y)dx\,dy = K\) and \( S \) is the surface of the sphere \( x^2 + y^2 + z^2 = 4 \) then \( K =\)
- \(\frac{64\pi}{3}\)
- \(\frac{16\pi}{3}\)
- \(\frac{32\pi}{3}\)
- \(\frac{8\pi}{3}\)
Answer: A
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If \( C \) is the square formed by the lines \( x = \pm 1, y = \pm 1 \) then \(\oint_C (x^2 + xy)dx + (x^2 + y^2)dy =\)
- 0
- 1
- 2
- 3
Answer: A
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If \( S \) is the surface of \( x^2 + y^2 + z^2 = a^2 \) above the \( xy \)-plane and \( F = y\mathbf{i} + (x - 2xz)\mathbf{j} - xy\mathbf{k} \) then \(\iint_S (\nabla \times F) \cdot \mathbf{n}\,dS =\)
- 0
- \(\overline{0}\)
- 1
- 2
Answer: A
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If \( F = y\mathbf{i} + z\mathbf{j} + x\mathbf{k} \) and \( S \) is the surface of the sphere \( x^2 + y^2 + z^2 = 1 \) in the \( xy \)-plane then \(\iint_S (\nabla \times F) \cdot \mathbf{n}\,dS =\)
- 0
- \(\pi\)
- \(-\pi\)
- 1
Answer: C
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The area of a plane region bounded by the closed curve \( C : x = a \cos t, y = a \sin t \) is
- \( 2\pi a^2 \)
- \( \pi a^2 \)
- \( 4\pi a^2 \)
- \( \frac{4}{3}\pi a^2 \)
Answer: B
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The vector integral theorem which transforms surface integral into volume integral is
- Stokes's theorem
- Green's theorem
- Gauss's divergence theorem
- Cauchy's theorem
Answer: C
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The value of \(\oint_C (x^2 + y^2)ds\) where C is the circle \(x^2 + y^2 = 4\) is:
- \(8\pi\)
- \(16\pi\)
- \(32\pi\)
- \(64\pi\)
Answer: B
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If \(\vec{F} = (x^2 + y)\mathbf{i} + (y^2 + x)\mathbf{j}\), then \(\int_C \vec{F} \cdot d\vec{r}\) along the parabola \(y = x^2\) from (0,0) to (1,1) is:
- \(\frac{5}{6}\)
- \(\frac{7}{6}\)
- \(\frac{11}{6}\)
- \(\frac{13}{6}\)
Answer: C
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The flux of \(\vec{F} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}\) through the surface \(x^2 + y^2 + z^2 = 9\) is:
- \(36\pi\)
- \(108\pi\)
- \(144\pi\)
- \(288\pi\)
Answer: B
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The work done by \(\vec{F} = y\mathbf{i} + z\mathbf{j} + x\mathbf{k}\) around the triangle with vertices (1,0,0), (0,1,0), (0,0,1) is:
- \(\frac{1}{2}\)
- \(-\frac{1}{2}\)
- \(\frac{3}{2}\)
- \(-\frac{3}{2}\)
Answer: D
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The value of \(\iint_S (x dy dz + y dz dx + z dx dy)\) where S is the surface of the cube \(0 \leq x,y,z \leq 1\) is:
- 0
- 1
- 2
- 3
Answer: D
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If \(\vec{F} = (2xy + z^3)\mathbf{i} + x^2\mathbf{j} + 3xz^2\mathbf{k}\), then \(\int_C \vec{F} \cdot d\vec{r}\) from (1,1,1) to (2,1,1) along \(y = 1\), \(z = 1\) is:
- 3
- 4
- 5
- 6
Answer: C
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The circulation of \(\vec{F} = -y\mathbf{i} + x\mathbf{j}\) around the ellipse \(\frac{x^2}{4} + \frac{y^2}{9} = 1\) is:
- \(6\pi\)
- \(12\pi\)
- \(24\pi\)
- \(36\pi\)
Answer: B
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The flux of \(\vec{F} = x^2\mathbf{i} + y^2\mathbf{j} + z^2\mathbf{k}\) through the cylinder \(x^2 + y^2 = 4\), \(0 \leq z \leq 5\) is:
- \(40\pi\)
- \(80\pi\)
- \(120\pi\)
- \(160\pi\)
Answer: D
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The value of \(\oint_C (x^2 - y^2)dx + 2xy dy\) where C is the square with vertices (0,0), (1,0), (1,1), (0,1) is:
- 0
- 1
- 2
- 4
Answer: A
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The surface integral \(\iint_S (x + y + z)dS\) over the plane \(x + y + z = 1\) in the first octant is:
- \(\frac{\sqrt{3}}{6}\)
- \(\frac{\sqrt{3}}{3}\)
- \(\frac{\sqrt{3}}{2}\)
- \(\sqrt{3}\)
Answer: C